Question #248045

An airplane passenger has 100 cm

3

of air in his stomach just before the plane takes off sea

-

level airport. What volume will the air have at cruising altitude if cabin pressure drops to

7.50 x 10

4

Pa?



1
Expert's answer
2021-10-08T11:46:54-0400

Solution;

At seal level, take atmospheric pressure as the initial pressure;

P=1.013×105N/m2P=1.013×10^5N/m^2

Volume of air; V=100cm3V=100cm^3

Pressures drops to,P=7.50×104N/m2P'=7.50×10^4N/m^2

Assuming temperature remains the same,we get the relation;

PV=PVPV=P'V'

So the new volume will be;

V=PVPV'=\frac{PV}{P'}

By substitution;

V=1.013×105×1007.5×104V'=\frac{1.013×10^5×100}{7.5×10^4}

V=135.06cm3V'=135.06cm^3




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