An airplane passenger has 100 cm
3
of air in his stomach just before the plane takes off sea
-
level airport. What volume will the air have at cruising altitude if cabin pressure drops to
7.50 x 10
4
Pa?
Solution;
At seal level, take atmospheric pressure as the initial pressure;
"P=1.013\u00d710^5N\/m^2"
Volume of air; "V=100cm^3"
Pressures drops to,"P'=7.50\u00d710^4N\/m^2"
Assuming temperature remains the same,we get the relation;
"PV=P'V'"
So the new volume will be;
"V'=\\frac{PV}{P'}"
By substitution;
"V'=\\frac{1.013\u00d710^5\u00d7100}{7.5\u00d710^4}"
"V'=135.06cm^3"
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