Answer to Question #201487 in Molecular Physics | Thermodynamics for Ankush

Question

How much heat is lost by 2.50 kg of sand on a beach if the warmest part  of the day is 35.0°C and it cools to 3.00°C at night (c=840 J/kgoC)?

Answer 1

$Q=cm\Delta{T}=840J/kg\degree{C}\times2.50kg\times(35.0\degree{C}-3.00\degree{C})=67200J=67.2kJ$

Answer: 67.2 kJ