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Answer to Question #201487 in Molecular Physics | Thermodynamics for Ankush
Question #201487
How much heat is lost by 2.50 kg of sand on a beach if the warmest part of the day is 35.0°C and it cools to 3.00°C at night (c=840 J/kgoC)?
Expert's answer
"Q=cm\\Delta{T}=840J\/kg\\degree{C}\\times2.50kg\\times(35.0\\degree{C}-3.00\\degree{C})=67200J=67.2kJ"
Answer: 67.2 kJ
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