Question #111932

A 1-kg block of ice is at -15° C. 4 x 105 J of heat is added to the ice block. NOTE: (a) should be divided into two parts: how much heat is needed to raise the temperature of the ice to 0 °C, and how much heat is required to melt it; then compare that sum total to 4.0 x 105 J (the specific heat to use for ice is provided in the accompanying sheet to this homework)


(a) Does it fully melt?

(b) What is the final overall temperature?

Expert's answer

a)


Q1=(1)(2060)(15)=30900 JQ_1=(1)(2060)(15)=30900\ J

Q2=(1)(335000)=335000 JQ_2=(1)(335000)=335000\ J

Q=335000+30900=365900 J<400000 JQ=335000+30900=365900\ J<400000\ J

So, all ice melted.

b)


(1)(4200)(T0)=400000365900(1)(4200)(T-0)=400000-365900

T=8.1°CT=8.1\degree C


LATEST TUTORIALS
APPROVED BY CLIENTS