Solution.
t = 10 minutes =600 seconds ;
N = 33W;
"\\eta" = 6 %;
The efficiency ratio is the ratio of useful work to full work multiplied by 100%:
"\\eta" = (Auseful/ Afull)"\\sdot" 100%;
Afull = N "\\sdot" t;
Afull =33W "\\sdot" 600 seconds = 19800J;
W = Auseful = ("\\eta""\\sdot" Afull)/100%;
W = (6 % "\\sdot" 19800J)/100% = 1188 J;
Answer: W = 1188 J.
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