Solution.
t = 10 minutes =600 seconds ;
N = 33W;
= 6 %;
The efficiency ratio is the ratio of useful work to full work multiplied by 100%:
= (Auseful/ Afull) 100%;
Afull = N t;
Afull =33W 600 seconds = 19800J;
W = Auseful = ( Afull)/100%;
W = (6 % 19800J)/100% = 1188 J;
Answer: W = 1188 J.
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