Solution.
"t = 10 minutes;\n\nN = 33W;\n\n\u03b7 = 6\\%;"
The efficiency ratio is the ratio of useful work to full work multiplied by 100%:
"\\eta=\\dfrac{A_u}{A_f}\\sdot100\\%;"
"A_f = N \u22c5 t; t =600 seconds ;\n\nA_f =33 \u22c5 600 = 19800J;"
"W = A_u =\\dfrac{\\eta\\sdot A_f }{100\\%};W =\\dfrac{6\\%\\sdot 19800J }{100\\%}=1188J;"
Answer:"W=1188J."
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