Solution.
t=10minutes;N=33W;η=6%;t = 10 minutes; N = 33W; η = 6\%;t=10minutes;N=33W;η=6%;
The efficiency ratio is the ratio of useful work to full work multiplied by 100%:
η=AuAf⋅100%;\eta=\dfrac{A_u}{A_f}\sdot100\%;η=AfAu⋅100%;
Af=N⋅t;t=600seconds;Af=33⋅600=19800J;A_f = N ⋅ t; t =600 seconds ; A_f =33 ⋅ 600 = 19800J;Af=N⋅t;t=600seconds;Af=33⋅600=19800J;
W=Au=η⋅Af100%;W=6%⋅19800J100%=1188J;W = A_u =\dfrac{\eta\sdot A_f }{100\%};W =\dfrac{6\%\sdot 19800J }{100\%}=1188J;W=Au=100%η⋅Af;W=100%6%⋅19800J=1188J;
Answer:W=1188J.W=1188J.W=1188J.
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