Answer to Question #97006 in Mechanics | Relativity for Stephen okungbowa

Question

A car starts from a check point P and comes to rest at a check point Q,8km away in 4 minutes. It has first, a uniform acceleration for 50 seconds, then a constant speed, and brought to rest with uniform retardation after 30 seconds. Sketch a velocity time graph for the motion and find,maximum speed, acceleration and retardation.

Answer 1

Maximum speed:

$$v=40\frac{m}{s}$$

Acceleration:

$$a_1=\frac{v}{t_1}=\frac{40}{50}=0.8\frac{m}{s^2}$$

$$a_2=\frac{v}{t_2}=\frac{40}{30}=1.33\frac{m}{s^2}$$