Question #97006
A car starts from a check point P and comes to rest at a check point Q,8km away in 4 minutes. It has first, a uniform acceleration for 50 seconds, then a constant speed, and brought to rest with uniform retardation after 30 seconds. Sketch a velocity time graph for the motion and find,maximum speed, acceleration and retardation.
1
Expert's answer
2019-10-22T10:25:02-0400


Maximum speed:


v=40msv=40\frac{m}{s}

Acceleration:


a1=vt1=4050=0.8ms2a_1=\frac{v}{t_1}=\frac{40}{50}=0.8\frac{m}{s^2}

a2=vt2=4030=1.33ms2a_2=\frac{v}{t_2}=\frac{40}{30}=1.33\frac{m}{s^2}


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Comments

Vilret
11.03.23, 11:25

Good

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