the maximum height at which the arrow will fly relative to its tip
u - initial speed;
α - angle to the horizontal;
g -acceleration of gravity (10 m/s^2);
H= 15 m;
the time of flight of an arrow to its maximum height (from tip):
t≈1.73 s;
the time of flight of an arrow from the maximum height to the ground:
"T=\\sqrt{\\frac{2 \\times (H+h)}{g}}"h-the initial height of the tip;
T≈1.82;
the distance at which the arrow falls:
L≈35.5m
Answer 35.5m
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