Mass of the one block:
"m = \\rho V"Volume of one block:
"V = S*h"According to the condition:
"h = 50cm = 0.5m"Pressure force:
"F = P = mg"Respectively:
"F = P = \\rho Vg = \\rho Shg"Determine the pressure:
"p = F\/S = {\\rho Shg \\over S} = \\rho gh"We obtain the initial formula for calculating the pressure:
"p = 68(kg\/m^3)*9.8(N\/kg)*0.5(m) = 333.2(N\/m^2) = 333.2(Pa)""333.2Pa \\approx 333Pa"
Answer: e) 333 Pa
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