Let the y-axis is directed toward North and x-axis toward West. Then
"S_x=S_{1x}+S_{2x}+S_{3x}""S_x=0+4-5\\cos 45^{\\circ}=0.5\\:\\rm{m}"
"S_y=S_{1y}+S_{2y}+S_{3y}"
"S_y=3+0-5\\sin 45^{\\circ}=-0.5\\:\\rm{m}"
The magnitude of resultant displaement
"S=\\sqrt{S_x^2+S_y^2}=\\sqrt{0.5^2+(-0.5)^2}=0.7\\:\\rm{m}"Direction
"\\theta=\\tan^{-1}\\frac{S_y}{S_x}=\\tan^{-1}\\frac{-0.5}{0.5}=-45^{\\circ}"(45 degree South of West)
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