Assuming that a rock was dropped without the initial velocity, one can use the following relation between the distance, acceleration and time of flight:
where gZ is the acceleration of gravity on Zeus. Deriving its value from the exression above, one can obtain:
"g_Z = \\frac{2 H}{t^2}."Substituting the numerical values, we get:
Answer: 1.2 m/s2
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