Question #85462

If vector A=Axi+Ayj+Azk,
B=Bxi+Byj+Bzk and
C=Cxi+Cyj+Czk
Show that the scalar triple product of the vector is[Ax Ay Az][Bx By Bz ][Cx Cy Cz]
Note:the bracket above is a 3 by 3 matrix
1

Expert's answer

2019-02-25T12:28:07-0500

Answer on Question #85462, Physics / Other

If vector A=Axi+Ayj+Azk\mathbf{A} = A_{x}\mathbf{i} + A_{y}\mathbf{j} + A_{z}\mathbf{k}, B=Bxi+Byj+Bzk\mathbf{B} = B_{x}\mathbf{i} + B_{y}\mathbf{j} + B_{z}\mathbf{k} and C=Cxi+Cyj+Czk\mathbf{C} = C_{x}\mathbf{i} + C_{y}\mathbf{j} + C_{z}\mathbf{k}.

Show that the scalar triple product of the vector is [AxAyAz][BxByBz][CxCyCz][A_x A_y A_z][B_x B_y B_z ][C_x C_y C_z].

Solution:

The vector product by definition


[B×C]=ijkBxByBzCxCyCz=i(ByCzBzCy)+j(BzCxBxCz)+k(BxCyByCx)[ \mathbf {B} \times \mathbf {C} ] = \left| \begin{array}{c c c} \mathbf {i} & \mathbf {j} & \mathbf {k} \\ B _ {x} & B _ {y} & B _ {z} \\ C _ {x} & C _ {y} & C _ {z} \end{array} \right| = \mathbf {i} \big (B _ {y} C _ {z} - B _ {z} C _ {y} \big) + \mathbf {j} (B _ {z} C _ {x} - B _ {x} C _ {z}) + \mathbf {k} (B _ {x} C _ {y} - B _ {y} C _ {x})


The scalar product by definition


(AB)=AxBx+AyBy+AzBz(\mathbf {A} \cdot \mathbf {B}) = A _ {x} B _ {x} + A _ {y} B _ {y} + A _ {z} B _ {z}


So, for the triple product we obtain


(A[B×C])=Ax(ByCzBzCy)+Ay(BzCxBxCz)+Az(BxCyByCx)=AxAyAzBxByBzCxCyCz\begin{array}{l} (\mathbf {A} \cdot [ \mathbf {B} \times \mathbf {C} ]) = A _ {x} \big (B _ {y} C _ {z} - B _ {z} C _ {y} \big) + A _ {y} (B _ {z} C _ {x} - B _ {x} C _ {z}) + A _ {z} \big (B _ {x} C _ {y} - B _ {y} C _ {x} \big) \\ = \left| \begin{array}{c c c} A _ {x} & A _ {y} & A _ {z} \\ B _ {x} & B _ {y} & B _ {z} \\ C _ {x} & C _ {y} & C _ {z} \end{array} \right| \\ \end{array}


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