3. A circular steel wire 2.00 m long must stretch no more than 0.25 cm when a tensile force of 400 N is applied to each end of the wire. What minimum diameter is required for the wire?
d=4FlπE∆l=0.2 mm.d=\sqrt\frac{4Fl}{\pi E∆l}=0.2~mm.d=πE∆l4Fl=0.2 mm.
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