Answer to Question #347138 in Mechanics | Relativity for Jane

Question

1. A 0.120-kg, 50.0-cm-long uniform bar has a small 0.055-kg mass glued to its left end and a small 0.110-kg mass glued to the other end. The two small masses can each be treated as point masses. You want to balance this system horizontally on a fulcrum placed just under its center of gravity. How far from the left end should the fulcrum be placed?

Answer 1

$M_1=M_2,$

$m_1gx+mg(x-\frac l2)=m_2g(l-x),$

$x=30~cm.$