Question #345972

How much work must be done to a proton to accelerate it from rest to 0.998c.


1
Expert's answer
2022-05-30T15:17:56-0400
W=mc21v2/c2mc2=mc2(11v2/c21)W=\frac{mc^2}{\sqrt{1-v^2/c^2}}-mc^2=mc^2(\frac{1}{\sqrt{1-v^2/c^2}}-1)

W=1.671027(3108)2(110.99821)=2.2109JW=1.67*10^{-27}*(3*10^8)^2(\frac{1}{\sqrt{1-0.998^2}}-1)\\ =2.2*10^{-9}\:\rm J


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