Answer to Question #345972 in Mechanics | Relativity for larah

Question #345972

How much work must be done to a proton to accelerate it from rest to 0.998c.


1
Expert's answer
2022-05-30T15:17:56-0400
"W=\\frac{mc^2}{\\sqrt{1-v^2\/c^2}}-mc^2=mc^2(\\frac{1}{\\sqrt{1-v^2\/c^2}}-1)"

"W=1.67*10^{-27}*(3*10^8)^2(\\frac{1}{\\sqrt{1-0.998^2}}-1)\\\\\n=2.2*10^{-9}\\:\\rm J"


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS