Find the approximate angle between vectors: π = (2, 3, 5) and πβ = (1, 6, -4).
"\\alpha=\\arccos\\frac{2\\cdot 1+3\\cdot 6-5\\cdot 4}{\\sqrt{2^2+3^2+5^2}\\cdot \\sqrt{1^2+6^2+4^2}}=90\u00b0."
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