Question #269549

2. Block 1 and block 2, with masses m1 = 5kg and m2 = 2kg, are connected by a system of massless, inextensible ropes and massless pulleys as shown in Fig. 2. (a) (Marks: 2) Draw the complete free body force diagram of the system. (b) (Marks: 4) Solve for the accelerations of block 2 and block 1. Assume that downward direction is positive. (c) (Marks: 2) Calculate the tensions in each rope


1
Expert's answer
2021-11-21T17:32:05-0500

(a)



(b)

Let acceleration of m1 will be a m/s2 and acceleration of m2 will be a2\frac{a}{2} m/s2

m1g2T=m1a5×102T=5a502T=5am2gT=m2a22×10T=2×a220T=aT=20a502(20a)=5a5040+2a=5a10=3aa=103=3.33  m/s2m_1g -2T =m_1a\\ 5 \times 10 -2T = 5a \\ 50 -2T = 5a \\ m_2g -T = m_2 \frac{a}{2} \\ 2 \times 10 -T = 2 \times \frac{a}{2} \\ 20 -T = a \\ T = 20 -a \\ 50 -2(20-a) = 5a \\ 50 -40 + 2a = 5a \\ 10 = 3a \\ a = \frac{10}{3} = 3.33 \;m/s^2

(c)

20T=3.3320 -T = 3.33

T=203.33=16.67  NT = 20 -3.33 = 16.67 \;N (on m2)

Tension of m1 =2T=2×16.67=33.34  N= 2T = 2 \times 16.67 = 33.34 \;N


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