Question #269454

The moon is 3.9 × 105 km from Earth's center and 1.5 × 108 km from the Sun's center. The masses of earth and the sun are 6.0 × 1024 kg and 2.0 × 1030 kg, respectively. Find the ratio of the gravitational fields due to Earth and the Sun at the center of the Moon.

1
Expert's answer
2021-11-22T15:11:19-0500

The gravitational force due to moon by Earth is


F=G(MEarthMMoon)d2F=\frac{G(M_{Earth}M_{Moon})}{d^2}

F=6.67×1011(6×1024×7.3×1022)(3.9×105)2=1.92×1026NF=\frac{6.67×10^{-11}(6×10^{24}×7.3×10^{22})}{(3.9×10^5)^2}=1.92×10^{26} N

The gravitational force due to Moon by Sun is

F=G(MSunMMoon)d2F=\frac{G(M_{Sun}M_{Moon})}{d^2}

F=6.67×1011(2×1030×7.3×1022)(1.5×108)2=3.24×1034NF=\frac{6.67×10^{-11}(2×10^{30}×7.3×10^{22})}{(1.5×10^8)^2}=3.24×10^{34}N


The ratio of gravitation force due to earth and sun on the centre of moon is

3.24×10341.92×1026=1.69×104\frac{3.24×10^{34}}{1.92×10^{26}}=1.69×10^4





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