Joana Marie is a swimmer. She swims directly across a river flowing at 4 m/s with a velocity of 2 m/s. What will be the actual velocity of Joana Marie relative to the river? Determine its angle.
Solution.
vr=4m/s;v_r=4 m/s;vr=4m/s;
vs=2m/s;v_s =2 m/s;vs=2m/s;
v=vr2+vs2;v=\sqrt{v_r^2+v_s^2};v=vr2+vs2;
v=42+22=4.47m/s;v=\sqrt{4^2+2^2}=4.47 m/s;v=42+22=4.47m/s;
tanθ=vsvr;tan\theta=\dfrac{v_s}{v_r};tanθ=vrvs;
tanθ=24=0.5;tan\theta=\dfrac{2}{4}=0.5;tanθ=42=0.5; θ=27o;\theta=27^o;θ=27o;
Answer: v=4.47m/s;θ=27o.v=4.47 m/s; \theta=27^o.v=4.47m/s;θ=27o.
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