Explanations & Calculations
- Let's assume that this satellite is displaced into the desired orbit at that height so it is meant to follow a circular path around the earth.
- During that journey, the gravitation acts on it perpendicular to its trajectory as the gravitation always directs toward the center of the earth.
- So the force generated due to the gravitation: mg acts in the same way.
- Since the force & the line of motion is always perpendicular to each other, it performs no work.
- So the work done by the gravitation is 0.
- It only prvides the force needed to move in a cicular path.
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