Question #228797

On sensing danger two birds Va=i+4j +3k and Vb=4i+2j-4k relative to a stationary observer. How far apart are the two bird after 5secs

Expert's answer

V=3i2j7k,\vec V=3\vec i-2\vec j-7\vec k,

V=32+(2)2+(7)2=7.87 ms,V=\sqrt{3^2+(-2)^2+(-7)^2}=7.87~\frac ms,

s=Vt=39.4 m.s=Vt=39.4~m.


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