Question #228498
A sphere or radius moving with velocity through a fluid experiencces a retarding Force given by f=6ry vz nx where n is the viscosity of the liquid.use method of dimension to find value of x,y,z
1
Expert's answer
2021-08-23T14:12:13-0400

Gives

F=6πrηvtF=6\pi r\eta v_t

F=6ryvznxF=6r^yv^zn^x

Dimensions

F=[M1L1T2]F=[M^1L^1T^{-2}]

r=[L]v=[LT1]r=[L]\\v=[LT^{-1}]

η=[M1L1T1]\eta=[M^1L^{-1}T^{-1}]


[M1L1T2]=6[L]x[LT1]y[M1L1T1]zx=1,y=1,z=1[M^1L^{-1}T^{-2}]=6[L]^x[LT^{-1}]^y[M^1L^{-1}T^{-1}]^z\\x=1,y=1,z=1




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