Question #229076

An axle with a diameter of 100mm has a force of 10N applied to it, what is the torque at the wheel?


1
Expert's answer
2021-08-24T14:42:24-0400

d=100mm=0.1md = 100mm = 0.1m

r=d2=0.05mr = \frac{d}{2}= 0.05m

F=10NF = 10N

τ=Fr=100.05=0.5Nm\tau = Fr = 10*0.05 = 0.5N*m


Answer: τ=0.5Nm\text{Answer: }\tau = 0.5N*m


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