An axle with a diameter of 100mm has a force of 10N applied to it, what is the torque at the wheel?
d=100mm=0.1md = 100mm = 0.1md=100mm=0.1m
r=d2=0.05mr = \frac{d}{2}= 0.05mr=2d=0.05m
F=10NF = 10NF=10N
τ=Fr=10∗0.05=0.5N∗m\tau = Fr = 10*0.05 = 0.5N*mτ=Fr=10∗0.05=0.5N∗m
Answer: τ=0.5N∗m\text{Answer: }\tau = 0.5N*mAnswer: τ=0.5N∗m
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments