Answer to Question #208484 in Mechanics | Relativity for Coleman

Question

A man walk from a point A and walk a distance of 8.0 km due northeast to point B from B he then walks 4.0 km due southeast to point x. Calculate the shortest distance between And x.

Answer 1

Gives

AB distance move north east direction

Man walk from Ato B=8km

Bx distance moves sound east

Next man walk B to x =4km

$AX^2=BA^2+BX^2$

$AX=\sqrt{8^2+4^2}=\sqrt{80}=8.94m$