relative to the Earth, spaceship A moves in one direction with speed 0.8c and another spaceship, B, moves in the opposite direction with speed 0.6c. What is the speed of spaceship A as measured by B?
For an observer on Earth:\text{For an observer on Earth:}For an observer on Earth:
vEA=0.8cv_{EA} = 0.8cvEA=0.8c
vEB=−0.6cv_{EB}= -0.6cvEB=−0.6c
For the observer on the B ship: \text{For the observer on the B ship: }For the observer on the B ship:
vBE=0.6cv_{BE}= 0.6cvBE=0.6c
according to the Lorentz velocity addition:\text{according to the Lorentz velocity addition:}according to the Lorentz velocity addition:
vBA=vEA+vBE1+vBEc2vEA;v_{BA}= \frac{v_{EA}+v_{BE}}{1+\frac{v_{BE}}{c^2}v_{EA}};vBA=1+c2vBEvEAvEA+vBE;
vBA=0.8c+0.6c1+0.6cc20.8c=1.4c1.48≈0.95cv_{BA}= \frac{0.8c+0.6c}{1+\frac{0.6c}{c^2}0.8c}=\frac{1.4c}{1.48}\approx0.95cvBA=1+c20.6c0.8c0.8c+0.6c=1.481.4c≈0.95c
Answer: vBA≈0.95c\text{Answer: }v_{BA}\approx0.95cAnswer: vBA≈0.95c
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