Answer to Question #205187 in Mechanics | Relativity for :-)

Question

Ben has a gold bar that weighs 72N. He then suspended the gold bar by a light cord. When the gold bar is fully immersed in water (ρwater = 1.00 ×10^3 kg/m^-3), the tension in the cord is 40N. When the gold bar is fully immersed in an unknown liquid, the tension is 25N. What is the density of the unknown liquid?

Answer 1

The tension in the cord:

$T=mg-\rho gV$

where mg is the weight of the bar,

$\rho$ is density of liquid,

V is volume of the bar.

$V=\frac{mg-T}{\rho g}=\frac{72-40}{1000\cdot9.8}=3.27\cdot10^{-3}\ m^3$

For unknown liquid:

$\rho=\frac{mg-T}{gV}=\frac{72-25}{9.8\cdot3.27\cdot10^{-3}}=1.467\cdot10^2 \ kg/m^3$