Question

A falling body has an initial velocity of 200cm/seconds.How far will it drop before its velocity becomes 10000 cm/seconds.

Answer 1

Well, we have given initial and final velocities and we have the value of g=9.81 m/s^2. We can find h (distance) easily:

$h=\frac{V^2(final)-V^2(initial)}{2\times g}$ = $\frac{100^2-2^2}{2\times 9.81}=500.75 m$

It reaches to drop to 500.75 metr.