A falling body has an initial velocity of 200cm/seconds.How far will it drop before its velocity becomes 10000 cm/seconds.
Well, we have given initial and final velocities and we have the value of g=9.81 m/s^2. We can find h (distance) easily:
"h=\\frac{V^2(final)-V^2(initial)}{2\\times g}" = "\\frac{100^2-2^2}{2\\times 9.81}=500.75 m"
It reaches to drop to 500.75 metr.
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