Answer to Question #159706 in Mechanics | Relativity for Dr. Horus

Question #159706

A 200 g ball is shot up a vertical

column of viscous liquid with an

initial velocity of 10 m/s Assuming

the force impeding the ball's motion

because of the viscosity of the liquid

is constant at 4.5 N, calculate how

high the ball goes before coming to

rest.



1
Expert's answer
2021-01-31T19:26:38-0500

When a ball is hit upwards the maximum height of a projectile is given by


H=u2y/2gH=u^2y/2g

uuo yy =uuo sinsinθ\theta

mass=200gg

=0.2kg

innitial velocity(u)u) =10m/s10m/s

in this case, we can get the normal force acting on a body vertically due to gravity.

ffm=mgmg

=0.29.80.2*9.8

=1.96N1.96N

viscosity of the liquid=4.5N4.5N

tanθtan\theta =4.5/1.96=4.5/1.96

tantan -1=2.2959

θ\theta =66.46=66.460


from hhmax== u2sin(θu^2*sin(\theta)2)^2 /2g/2g


== 102sin(66.46)210^2*sin(66.46)^2 /29.8/2*9.8


=4.2884m=4.2884m



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