Question #159433

A car of mass 9500kg is moving up a cliff from rest with a velocity of v=(3t^2 + 2t)î +5j m/s for 1 minute.If the slope of the cliff is 1,what distance was covered by the car in 1minute


1
Expert's answer
2021-01-28T17:09:34-0500
x(t)=3t33+2t22=t3+t2y(t)=5tx(t)=3\frac{t^3}{3}+2\frac{t^2}{2}=t^3+t^2\\y(t)=5t

x(60)=603+602=219600 my(60)=5(60)=300 ms=2196002+3002=219600 mx(60)=60^3+60^2=219600\ m\\y(60)=5(60)=300\ m\\s=\sqrt{219600^2+300^2}=219600\ m


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