A car of mass 9500kg is moving up a cliff from rest with a velocity of v=(3t^2 + 2t)î +5j m/s for 1 minute.If the slope of the cliff is 1,what distance was covered by the car in 1minute
"x(60)=60^3+60^2=219600\\ m\\\\y(60)=5(60)=300\\ m\\\\s=\\sqrt{219600^2+300^2}=219600\\ m"
Comments
Leave a comment