A bullet of mass 10 g traveling horizontally with a velocity of 300 ms- strikes a block of wood of mass 290 g which rests on a rough horizontal floor. After impact, the block and bullet move together and come to rest when the block has traveled a distance of 15 m. Calculate the coefficient of sliding friction between the block and the floor.
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Expert's answer
2020-11-30T14:59:28-0500
Initial speed of bullet before strike =300 m/sec and Block is at rest.Conservation of momentum before and after collision:
(10×300+290×0)×10−3=(10+290)×10−3×U
Where U is the block-bullet system just after the strike.
U=10m/esc
Now, equation of motion after the strike.
Fr=Ma−μR=Ma−μ(M×g)=Ma−μg=a......Eq[1]
Finally system get stopped so final speed is zero and before it travelled S=15 meter.
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