Answer
a) kinetic energy is
KE=mv22KE=\frac{mv^2}{2}KE=2mv2
Momentum is given by
P=mvv=PmP= mv\\v=\frac{P}{m}P=mvv=mP
Putting in kinetic energy become as
KE=mP22m2=P22mKE=\frac{mP^2}{2m^2}=\frac{P^2}{2m}KE=2m2mP2=2mP2 Hence proved
b) mass is given by
m=P22K=(25)22×275=1.136Kgm=\frac{P^2}{2K}=\frac{(25)^2}{2\times275}=1.136Kgm=2KP2=2×275(25)2=1.136Kg
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