Question #179769

A conducting sphere of radius 6.25 cm has a total charge of 10.50 x 10^(-9) C distributed uniformly on its surface area. Find the potential at (a) its surface, (b) any point inside the sphere, and (c) a distance of 5.0 cm from the center of the sphere. *


1
Expert's answer
2021-04-13T06:40:32-0400

Answer

(A)

Potential at surface

V=kqRV=(9×109)(10.50×109)0.0625=1512VV=\frac{kq}{R}\\V=\frac{(9\times10^9)(10.50\times10^{-9})}{0.0625}=1512V



(B)

Charge is at surface of shere so inside the sphere potential will be same as sphere, so

V=1512BVV=1512BV

(C)

r=5.0cm exist inside sphere so

V=1512voltsV=1512volts




Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS