Question

A conducting sphere of radius 6.25 cm has a total charge of 10.50 x 10^(-9) C distributed uniformly on its surface area. Find the potential at (a) its surface, (b) any point inside the sphere, and (c) a distance of 5.0 cm from the center of the sphere. *

Answer 1

Answer

(A)

Potential at surface

$V=\frac{kq}{R}\\V=\frac{(9\times10^9)(10.50\times10^{-9})}{0.0625}=1512V$

(B)

Charge is at surface of shere so inside the sphere potential will be same as sphere, so

$V=1512BV$

(C)

r=5.0cm exist inside sphere so

$V=1512volts$