Answer to Question #177909 in Field Theory for Jo-an Balicao

Question

Point charge q1= -5.00 nC at the origin and point charge q2 = +3.00 nC is on the x-axis at x= 3.00 cm. Point P is on the y-axis at y= 4.00 cm. a) Calculate the electric fields Ē1 and Ē2 at point P due to the charges q1 and q2. Express your results in terms of unit vectors. Use the results of part (a) to obtain the resultant field at P, expressed in unit vector form.

Answer 1

$$\vec{E}_1=\frac{(9\cdot10^9)(-5\cdot10^{-9})}{0.03^2}\vec{e}_x\\\vec{E}_1=-50000\vec{e}_x\frac{V}{m}$$

$$\vec{E}_2=\frac{(9\cdot10^9)(3\cdot10^{-9})}{0.04^2}\vec{e}_y\\\vec{E}_2=16875\vec{e}_y\frac{V}{m}\\ \\\vec{E}=(16875\vec{e}_y-50000\vec{e}_x)\frac{V}{m}$$