Question #89836

Show that the frequency of an electromagnetic wave undergoing reflection and transmission at an interface of two dielectrics remains invariant.

Expert's answer

Plane electromagnetic wave reads as:


E=E0eikxiωt\vec{E} = \vec{E_0}\, e^{i\vec{k}\cdot\vec{x} -i\omega t}

Transmitted and reflected wave looks analogously, but with different wavevector k\vec{k} , frequency ω\omega and amplitude E0\vec{E_0}.

Boundary conditions for EM field (the tangential component of E is continuous across the interface., the normal component of D is continuous, the normal component of B is continuous across the interface, the tangential component of H is continuous across the surface) are right at any moment of time.

Therefore, frequencies of transmitted, reflected and incident ray are equal.


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