Question

Two oscillations along the same line are
described by the equations
x1= 0.03 cos (10π t)
and x2= 0.03 cos (12π t)
Obtain the equation describing the resultant
motion due to superposition of these two
oscillations.

Answer 1

The equation describing the resultant motion is given by formula

$$x=0.03 (\cos 10π t + \cos 12π t) (1)$$

Using (1) we got:

$$x=0.06 (\cos 11π t \cos -π t)= 0.06 (\cos 11π t \cos π t)$$

Answer:

$$0.06 (\cos 11π t \cos π t)$$