2019-05-16T04:31:59-04:00
The electric potential at any point is given
by ¢= xy(z²— 3xy). Calculate the electric field E at that point.
1
2019-05-27T10:52:41-0400
E = − ∇ ϕ = − ( ∂ x ϕ , ∂ y ϕ , ∂ z ϕ ) \mathbf{E} = -\nabla \phi = - (\partial_x \phi, \partial_y \phi, \partial_z \phi) E = − ∇ ϕ = − ( ∂ x ϕ , ∂ y ϕ , ∂ z ϕ )
∂ x ϕ = ∂ x ( x y z 2 − 3 x 2 y 2 ) = y z 2 − 6 x y 2 \partial_x \phi = \partial_x (xyz^2 - 3x^2 y^2) = yz^2 -6xy^2 ∂ x ϕ = ∂ x ( x y z 2 − 3 x 2 y 2 ) = y z 2 − 6 x y 2 ∂ y ϕ = x z 2 − 6 x 2 y \partial_y\phi =xz^2 - 6x^2 y ∂ y ϕ = x z 2 − 6 x 2 y ∂ z ϕ = 2 x y z \partial_z \phi = 2xyz ∂ z ϕ = 2 x yz
E = ( 6 x y 2 − y z 2 , 6 x 2 y − x z 2 , − 2 x y z ) \mathbf{E} = (6xy^2 - yz^2, 6x^2 y - xz^2, -2xyz) E = ( 6 x y 2 − y z 2 , 6 x 2 y − x z 2 , − 2 x yz )
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