Question #88919
Using Ampere's law, obtain the expression for the magnetic field clue to a solenoid.
1
Expert's answer
2019-05-08T09:33:11-0400


Magnetic field inside the long solenoid can be treated as uniform and parallel to solenoids axis. This is also true for the point just at the end of the solenoid.At all the other points we can take the magnetic field to be 0. Following this assumptions and the Amper's law (in its integrative form)


lBdl=μ0Ienclosed\oint_l{Bdl} = \mu_0 I_{enclosed}

we can conclude that


BL=μ0NIB L=\mu_0 N I

and after all this


B=μ0NI/L=μ0nIB = {\mu_0 N I}/L={\mu_0 n I}

where n is a density of the turns of the wire in the solenoid


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