Answer to Question #88912 in Electricity and Magnetism for Shivam Nishad

Question

In the Bohr model, the electron of a hydrogen
atom moves in a circular orbit of radius
5.3 x 10^-11 m with a speed of 2.2 x 10^6 ms^-1. Determine its frequency and the current in the orbit.

Answer 1

Frequency of the electron is:

$$\nu=\frac{\omega}{2\pi}=\frac{v}{2\pi r}=\frac{2.2*10^{6}}{2*3.14 *5.3*10^{-11}}=6.6*10^{15} Hz$$

The current in the orbit is:

$$I=\frac{\Delta q}{\Delta t}=\frac{e}{T}=e\nu=1.6*10^{-19}*6.6*10^{15}=1.06*10^{-3} A$$