Question #87947

Three point charges A, B, and C sit on the corners of an equilateral triangle with side length 10cm. Each charge has a of magnitude 2.32 x 10-6 C with charge A and C being negative and B being positive, as shown in the diagram below. What is the net force on each of the point charges? Include vector diagrams for each charge in your answer.

Expert's answer

The vector diagram for each charge is:



where we take into account the fact that the magnitude of the Coulomb force of interaction between any pair of charges is equal to:


F1=kq2a2=91092.32210121024.85NF_1 = \frac{k q^2}{a^2} = \frac{9 \cdot 10^9 \cdot 2.32^2 \cdot 10^{-12}}{10^{-2}} \approx 4.85 \,N

As a result, the following values for the magnitudes of the net forces can be obtained:


FA=2F1cos60=F1=4.85NFB=2F1cos60=F1=4.85NFC=2F1cos30=3F1=8.40NF_A = 2F_1 \cos{60^\circ} = F_1 = 4.85 \, N\\ F_B = 2F_1 \cos{60^\circ} = F_1 = 4.85 \, N\\ F_C = 2F_1 \cos{30^\circ} = \sqrt{3} F_1 = 8.40 \, N

Answer: 4.85 N, 4.85 N, 8.40 N.



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