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Question #87936
Two stationary charged objects are 20.0 cm apart from each other. Object B is (-2.6mC) and object L is (-3.4mC). What is the electric field (provide the magnitude and direction) they generate at the midpoint between them?
Expert's answer
E
B
=
k
q
B
r
2
=
(
9
⋅
1
0
9
)
(
2.6
⋅
1
0
−
3
)
0.
1
2
=
2.34
⋅
1
0
9
N
C
E_B=\frac{kq_B}{r^2}=\frac{(9 \cdot 10^9)(2.6 \cdot 10^{-3})}{0.1^2}=2.34 \cdot 10^9 \frac{N}{C}
E
B
=
r
2
k
q
B
=
0.
1
2
(
9
⋅
1
0
9
)
(
2.6
⋅
1
0
−
3
)
=
2.34
⋅
1
0
9
C
N
Directed to the object B.
E
L
=
k
q
L
r
2
=
(
9
⋅
1
0
9
)
(
3.4
⋅
1
0
−
3
)
0.
1
2
=
3.06
⋅
1
0
9
N
C
E_L=\frac{kq_L}{r^2}=\frac{(9 \cdot 10^9)(3.4 \cdot 10^{-3})}{0.1^2}=3.06 \cdot 10^9 \frac{N}{C}
E
L
=
r
2
k
q
L
=
0.
1
2
(
9
⋅
1
0
9
)
(
3.4
⋅
1
0
−
3
)
=
3.06
⋅
1
0
9
C
N
Directed to the object L.
Net electric field:
E
=
E
L
−
E
B
=
3.06
⋅
1
0
9
−
2.34
⋅
1
0
9
=
7.2
⋅
1
0
8
N
C
E=E_L-E_B=3.06 \cdot 10^9-2.34 \cdot 10^9=7.2 \cdot 10^8 \frac{N}{C}
E
=
E
L
−
E
B
=
3.06
⋅
1
0
9
−
2.34
⋅
1
0
9
=
7.2
⋅
1
0
8
C
N
Directed to the object L.
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