Question #107539
A wire loop of resistance 10 ohm and radius 10 cm is kept in the plane of this paper in a uniform magnetic field B. The direction of B is perpendicular to the plane of the page and points out of it and its magnitude is increasing at the rate of 0.50Ts inverse. Determine the magnitude and direction of the induced current in the loop
1
Expert's answer
2020-04-02T10:50:31-0400


From the law of electromagnetic induction we write


ϵ=dBdtA=πr2dBdt\epsilon=\frac{dB}{dt}A=\pi r^2\frac{dB}{dt}

Then the current is


I=ϵR=πr2RdBdtI=\frac{\epsilon}{R}=\frac{\pi r^2}{R}\frac{dB}{dt}

I=(0.5)π0.1210=1.57 mAI=\frac{(0.5)⋅\pi⋅0.1 ^2}{10}=1.57\ mA


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