Question

An electron travels 0.01 m across an electric potential difference of 6 x 10^6 V. What is the force exerted on the electron?

Answer 1

Electric field =$\frac{potential \ difference (\Delta V)}{\Delta x}=\frac{6\times10^6}{0.01}=6\times10^8V/m$

Force =$q\times electric \ field =1.6\times10^{-19}\times6\times10^8=9.6\times10^{-11}N$