Question #106258
[img]https://upload.cc/i1/2020/03/23/lyospF.jpg[/img]


the question is in the picture,R=4
1
Expert's answer
2020-03-27T10:47:18-0400

Question


Given the following circuit:


(a) Determine the currents (i1, i2, and i3) in all branches by following the current direction as shown in figure 5.

(b) Hence, find Vab.


Solution

First, draw the loops:



(a) Write Kirchhoff's voltage law for the given circuit according to the drawn loops and Kirchhoff's current law for node a:


i1i2i3=0,57=(2+5)i1+6i2,5+10=(2+5)i1+(3+1)i3.i1=0.8723 A,i2=1.351 A,i3=2.223 A.i_1-i_2-i_3=0,\\ 5-7=(2+5)i_1+6i_2,\\ 5+10=(2+5)i_1+(3+1)i_3.\\ i_1=0.8723\text{ A},\\ i_2=-1.351\text{ A},\\ i_3=2.223\text{ A}.

(b) The voltage between the terminals a and b:


Vab=6i2+7=1.106 V.V_{ab}=6i_2+7=-1.106\text{ V}.


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