Question #106136
A spherical straight has a radius of 14.0 cm and a charge of 26.0 uC.Calculate the electric field and the electric potential at(a)r=10.0 cm (b)r=20.0 cm, and (c)r=14.0 cm from the centre.
1
Expert's answer
2020-03-25T11:06:26-0400

a) Since the sphere is conducting, the electric field inside it r=0.1 m<Rr=0.1\ m<R is zero


E=0NCE=0\frac{N}{C}

V=8.99109261060.14=1.67106VV=8.99\cdot 10^9\frac{26\cdot 10^{-6}}{0.14}=1.67\cdot 10^{6}V

b)


E=8.99109261060.22=5.84106NCE=8.99\cdot 10^9\frac{26\cdot 10^{-6}}{0.2^2}=5.84\cdot 10^{6}\frac{N}{C}

V=8.99109261060.2=1.17107VV=8.99\cdot 10^9\frac{26\cdot 10^{-6}}{0.2}=1.17\cdot 10^{7}V

c)


V=8.99109261060.14=1.67106VV=8.99\cdot 10^9\frac{26\cdot 10^{-6}}{0.14}=1.67\cdot 10^{6}V

E=8.99109261060.142=1.19107NCE=8.99\cdot 10^9\frac{26\cdot 10^{-6}}{0.14^2}=1.19\cdot 10^{7}\frac{N}{C}


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