Electric Circuits Answers

Questions: 3 894

Answers by our Experts: 3 489

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Search & Filtering

A 2.00 x 10^(-9) F capacitor with an initial charge of 5.10 x 10^(-6) C is discharged through a 1.30 Kohm resistor.
(i) Calculate the current in the resistor 9.00 s after the resistor is connected across the terminals of the capacitor.
(ii) What charge remains on the capacitor after 8.00s? Hence calculate the maximum current in the resistor.
A 10.0 x 10^(-6) F capacitor is charged by a 10.0V battery through a resistance R. The capacitor reaches a potential difference of 4.00V in a time interval of 3.00 s after charging begins. Find R
A charged capacitor is connected to a resistor and switch all in series. The circuit has a time constant of 1.50 s. Soon after the switch is closed, the charge of the capacitor is 75.0% of its initial charge.
(i) Find the time interval required for the capacitor to reach this charge.
(ii) If R = 250 Kiloohm, what is the value of C?
A capacitor consists of 2 parallel metal plates in air. The distance between the plates is 5.00mm and the capacitance is 72 x10^(-12) F. The potential difference between the plates is raised to 12.0V with a battery.
(i) Calculate the energy stored in the capacitor
(ii) The battery is then disconnected from the capacitor; the capacitor retains its charge. Calculate the energy stored in the capacitor if the distance between the plates is now increased to 10.00mm.
Hence account for the difference of your answer in the above two cases.
A capacitor consists of 2 parallel metal plates in air. The distance between the plates is 5.00mm and the capacitance is 72 x10^(-12) F. The potential difference between the plates is raised to 12.0V with a battery.
(i) Calculate the energy stored in the capacitor
(ii) The battery is then disconnected from the capacitor; the capacitor retains its charge. Calculate the energy stored in the capacitor if the distance between the plates is now increased to 10.00mm.
A capacitor consists of two parallel metal plates in air. The distance between the plates is 5.00mm and the capacitance is 72pF. The potential difference between the plates is raised to 12.0V with a battery.
(a) Calculate the energy stored in the capacitor.
(b) The battery is then disconnected from the capacitor; the capacitor retains its charge. Calculate the energy stored in the capacitor if the distance between the plates is now increased to 10.00mm. Account for the difference in your answer of (a) and (b) above.

Suppose the "vertical attenuator" of an A.C signal is set to 0.5v/Div and the probe factor is 10,if signal occupies 5 divisions vertically.What is the peak to peak voltages and the rms equivalent.


A parallel plate capacitor consists of 2 plates of area 1.00 x 10^(-2) m^2 placed a distance 2.00 x 10^(-2) m apart in air. The capacitor is charged so that the potential difference between the plates is 1000V. Calculate;
(i) the electric field between the plates(neglect edge effects)
(ii)the capacitance of the capacitor and the energy stored in the capacitor.
A hollow metal container with a small opening, standing on an insulating material, is given an electric charge. Explain how using such other apparatus as you may require, you would show that there is no charge on the inside of the container.
Explain what is mearnt by
(i) the potential
(ii)the electric field strength at a point in an electric field. State and explain how these quantities are related.