A typical incandescent bulb has an efficiency of about 10%. What current is needed for a bulb with a resistance of (1.5×10^2) Ω to output power of 6.0 W?
Solution;
P=I2RP=I^2RP=I2R
6=I2(1.5×102)6=I^2(1.5×10^2)6=I2(1.5×102)
I2=0.4I^2=0.4I2=0.4
I=0.6324AI=0.6324AI=0.6324A
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