Answer to Question #310550 in Electric Circuits for Diablo

Question

Given a resistor R1= 20ohms, R2= 20ohms, R3= 30ohms are connected in parallel. The next one is connected in series to obtain a total resistance of 10ohms. If P= 0.36KW, Find the Current

Answer 1

Solution;

Total resistance is give;

$R_T=10\Omega$

Power is ;

$P=0.35kW$

To obtain the current,I;

$P=I^2R$

$I^2=\frac{360}{10}=36$

$I=\sqrt{36}=6A$