Calculate the energy stored in a 5uf capacitor charge to 30 V
The information given is
The capacitance is C=5μFC=5\mu F\\C=5μF
The capacitor voltage is V=30 VV=30\;VV=30V
The stored energy is given by
U=12 C V2U=\dfrac{1}{2}\;C\;V^{2}U=21CV2
Evaluating numerically
U=12 5 μ (30 V)2=2250 μ JU=\dfrac{1}{2}\;5\;\mu\;(30\;V)^{2}=2250\;\mu\;JU=215μ(30V)2=2250μJ
The energy stored by the capacitor is
U=2250 μ JU=2250\;\mu\;JU=2250μJ
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