A 240 V two-bar electrical eadiator is rated 1 KW per bar. Calculate the resistance in the radiator circuit when one bar is switched on.
Solution.
V=240V;V=240V;V=240V;
P=1000W;P=1000W;P=1000W;
R−?;R-?;R−?;
P=V2R ⟹ R=V2P;P=\dfrac{V^2}{R}\implies R=\dfrac{V^2}{P};P=RV2⟹R=PV2;
R=24021000=57.6Ω;R=\dfrac{240^2}{1000}=57.6\Omega;R=10002402=57.6Ω;
Answer: R=57.6Ω.R=57.6\Omega.R=57.6Ω.
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