Given R1 = 10 Ohms
R2 = 15 Ohms
R3 = 5 Ohms

R1 and R2 are in parallel, therefore, R12 = R1 || R2
R12 = R121=R11+R21
R12 = R1+R2R1∗R2
R12 = 10∗1510+15=6Ohms
Now R12 and R3 are in series,
Therefore, Net equivalent Res. R = R12 + R3 = 6 + 5 = 11 Ohms
Therefore, Final Equivalent Res. = 11 Ohms
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