Question #290246

Find the magnetic field produced by the solenoid if the number of loops is 400

       and current passing through it is 5A. (Length of the solenoid is 40cm).



Expert's answer

We know that

B=μ0niB=\mu_0ni

n=Nl=4000.40=1000n=\frac{N}{l}=\frac{400}{0.40}=1000

N=400

L=0.40m

i=5A

Put value in equation


B=4×3.14×10−7×1000×5=6.28×10−3TB=4\times3.14\times10^{-7}\times1000\times5=6.28\times10^{-3}T

B=6.28×10−3TB=6.28\times10^{-3}T


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