Find the magnetic field produced by the solenoid if the number of loops is 400
and current passing through it is 5A. (Length of the solenoid is 40cm).
We know that
B=μ0niB=\mu_0niB=μ0ni
n=Nl=4000.40=1000n=\frac{N}{l}=\frac{400}{0.40}=1000n=lN=0.40400=1000
N=400
L=0.40m
i=5A
Put value in equation
B=6.28×10−3TB=6.28\times10^{-3}TB=6.28×10−3T
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